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49x^2+84x-32=0
a = 49; b = 84; c = -32;
Δ = b2-4ac
Δ = 842-4·49·(-32)
Δ = 13328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13328}=\sqrt{784*17}=\sqrt{784}*\sqrt{17}=28\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-28\sqrt{17}}{2*49}=\frac{-84-28\sqrt{17}}{98} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+28\sqrt{17}}{2*49}=\frac{-84+28\sqrt{17}}{98} $
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